f(x)=x^2(2lnx-3)+4x-1

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Solution for f(x)=x^2(2lnx-3)+4x-1 equation:


Simplifying
f(x) = x2(2lnx + -3) + 4x + -1

Multiply f * x
fx = x2(2lnx + -3) + 4x + -1

Reorder the terms:
fx = x2(-3 + 2lnx) + 4x + -1
fx = (-3 * x2 + 2lnx * x2) + 4x + -1

Reorder the terms:
fx = (2lnx3 + -3x2) + 4x + -1
fx = (2lnx3 + -3x2) + 4x + -1

Reorder the terms:
fx = -1 + 2lnx3 + 4x + -3x2

Solving
fx = -1 + 2lnx3 + 4x + -3x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = -1x-1 + 2lnx2 + 4 + -3x

Simplifying
f = -1x-1 + 2lnx2 + 4 + -3x

Reorder the terms:
f = 4 + 2lnx2 + -1x-1 + -3x

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